Algebra 1 Crap

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bi*moonpoet
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Algebra 1 Crap

Post by bi*moonpoet »

the directions are write an equation of the line that passes through the point and has the given slope.write the equation in slope-intercept form. i dont get it one of the problems is (-3,6),m=2 what am i suppose to do with that?
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bi*moonpoet
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Re: Algebra 1 Crap

Post by bi*moonpoet »

the faster you can help me the better
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Re: Algebra 1 Crap

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bi*moonpoet
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Re: Algebra 1 Crap

Post by bi*moonpoet »

i thought for it to be y-intercept it had to be set up like (0,6) with the zero in front
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Re: Algebra 1 Crap

Post by junglemonkey »

Just write the equation??



Pt ( -3, 6 ) m = 2



y - b = m (x-a)

y - 6 = 2 (x -(-3))

y - 6 = 2x +6

y = 2x + 12
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Re: Algebra 1 Crap

Post by Sam! »

I hated that stuff. I hated it. Hated it. Still do. Power to geometry!
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Doh!-Nut
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Re: Algebra 1 Crap

Post by Doh!-Nut »

If you have one point on the line, and the slope, you can use this simple POINT-SLOPE FORM to figure out the SLOPE-INTERCEPT form in a few easy steps, more fleshed out then Jungle said:



Standard:



y - y' = m(x - x')



Then, plug in your point and slope:



y - 6 = 2(x + 3)



And then change to slope-intercept form:



y - 6 = 2x + 6

[y = 2x + 12]



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