okay i can not get this to work, and i spent like 30 mins or more on it. ihate it its showing how one trig function equals the other by using the 8 fundimental identities
5+sec2 and you want to show how it equals 6+tan2
(the twos are squares)
Help
- Wheretogo
- Veteran
- Posts: 2318
- Joined: Mon Jan 26, 2004 2:45 am
- Contact:
Help
Why give up, why give in?
It's not enough, it never is.
So I will go on until the end.
We've become desolate.
It's not enough, it never is.
But I will go on until the end.
I've lost my way.
I've lost my way, but I will go on until the end.
Living is hard enough
Without you fucking up.
Until The End - Breaking Benjamin
It's not enough, it never is.
So I will go on until the end.
We've become desolate.
It's not enough, it never is.
But I will go on until the end.
I've lost my way.
I've lost my way, but I will go on until the end.
Living is hard enough
Without you fucking up.
Until The End - Breaking Benjamin
- PurplePoemPuppet
- Veteran
- Posts: 2468
- Joined: Fri Dec 27, 2002 2:46 pm
- Contact:
Re: Help
I'm assuming x is supposed to be in there, but I suppose it doesn't really matter.
sec^2 + 5 = tan^2 +6 <-- the problem you want to solve
(tan^2 + 1) = sec^2 <-- a trig identity
So substitute:
(tan^2 +1) + 5 = tan^2 +6 <-- (tan^2 + 1) is substituted for sec^2
tan^2 + 6 = tan^2 + 6 <-- add 5 + 1 = 6 and you have your answer
sec^2 + 5 = tan^2 +6 <-- the problem you want to solve
(tan^2 + 1) = sec^2 <-- a trig identity
So substitute:
(tan^2 +1) + 5 = tan^2 +6 <-- (tan^2 + 1) is substituted for sec^2
tan^2 + 6 = tan^2 + 6 <-- add 5 + 1 = 6 and you have your answer